Fill list and finish python loop

Question

I need help on a problem that asks me to fill in by adding data to a list until it is declared 'end'.

E=[]
i=0
E.append(input('Nome do elemento?'))
while (i!=fim):
  E.append(input('Nome do elemento?'))
  if i == fim:
    break

I made this code, but I can’t break it out of the loop.

Answer 1

In your example there are some errors:

1. end is not string
2. you are comparing end with a variable that contains an integer
3. while(!=end) already indicates if you type 'end' in the input it will break automatically without you having to do an if for it. But here the end is also not a string.

E=[]

i = input('Nome do elemento: ')
while (i != 'fim'):
    i = input('Nome do elemento: ')
    E.append(i)

print(E)

Answer 2

From what I understand you want to add names inside a list until you decide parar. For this, you can use the following algorithm:

cont = 0
elementos = list()
while True:
    cont += 1
    elementos.append(input(f'Nome do {cont}º elemento: '))

    resp = input('Fim [S/N]? ').upper()
    while (len(resp) != 1) or (resp not in 'SN'):
        print('\033[31mValor INVÁLIDO! Digite apenas "S" ou "N"!\033[m')
        resp = input('Fim [S/N]? ').upper()
    if resp == 'N':
        print(f'\033[32mA lista formada foi: {elementos}\033[m')
        break

Note that when we run the following algorithm we receive the following message: Nome do 1º elemento: . At this point we must enter the name and press Enter. Then we received the following message; Fim [S/N]? . If we wish to continue just type S and press enter. Then the algorithm will request the next name and so on.

Now, if we want to close, just type N and press enter. At this time the algorithm will display the list formed by all the elements previously typed and then will terminate its execution.