3
There is the possibility to return only one fragment of a page’s code with the AJAX
JQuery
?
What I want to do is:
I have a page where through the POST
send the ID with the AJAX
, and I am the body of a modal <div class="modal-body">
, but I would like to have another div to return the header of this modal <div class="modal-header">
.
Is there any way to call through the result of AJAX
each div
individually to change the HTML
via Javascript
?
Additional
What I have so far would be this:
<script>
function teste(){
var url = "&id="+teste;
$.ajax({
url: "conv_modal_results.php",
dataType:"HTML",
type: "POST",
data: url,
beforeSend: function(){
$('.modal-body').html('<div align="center"><img src="img/loading.gif" /></div>');
},
sucess: function(data){
setTimeout($('.modal-body').html(data),2000);
}
});
}
</script>
<input type="button" value="botaozinho" onClick="teste()">
<div class="modal fade">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">×</span></button>
<h4 class="modal-title">Carregando....</h4>
</div>
<div class="modal-body">
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Fechar</button>
</div>
</div><!-- /.modal-content -->
</div><!-- /.modal-dialog -->
</div><!-- /.modal -->
In conv_modal_results.php I have the following return
<div id="corpo_modal" class="row">
Aqui vai o corpo do modal...
</div>
What I want is to be able to add one more div
and be able to call each one individually in the result, using something like the .find()
of JQuery
to use only that piece of HTML
Yes it is possible. If you explain a little more what AJAX should return and show more of the structure code we can also answer with an example.
– Sergio