Add items to an Expandable List

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Add items to an Expandable List

Asked 8 years, 11 months ago

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I’m trying to use an Expandable List. In this Expandable List I intend to put as header "the categories of my products" and in the children items put "my products". However I’m getting the error "java.lang.IndexOutOfBoundsException: Invalid index 1, size is 1", when I try to insert the products into the categories(headers). Both the products and the categories I get them from my database.

LinkedHashMap <String, List<String>> expandableListDetail2 = new LinkedHashMap<String, List<String>>();

        List<String> categoria_header = new ArrayList<String>();
        int i=0;
        List<Producto> produtos;
        Database db = new Database(context);
        List<Categorias> categorias;

        categorias = db.getAllCategorias();

        for (i=0; i<categorias.size(); i++){

            expandableListDetail2.put(categorias.get(i).toString(), categoria_header);

            produtos = db.getAllProductos(categorias.get(i).toString());

               for(int j=0;j<produtos.size();j++) {
                   Log.d("Expandable","categoria->"+categorias.get(i).toString());
                   Log.d("Expan","get->"+produtos.get(0).getNomeProducto());
                   categoria_header.add(i,produtos.get(j).getNomeProducto());
               }
}

The problem is in produtos.get(j).getNomeProducto(). Anyone can help?

Produtos is a list with 1 item and you are trying to access the index 1 (second position).

– Jéf Bueno

2015/10/26 at 19:10
@jbueno my Dice starts at 0 (int j=0).

– porthfind

2015/10/26 at 19:13
I saw that. I just said what the error says, but it really doesn’t seem to make much sense. You can put in the question the value of produtos.size()?

– Jéf Bueno

2015/10/26 at 19:17
Are you sure the mistake is in produtos.get(j).getNomeProducto()?

– ramaral

2015/10/26 at 19:18
@jbueno is putting products.size() because I think that’s what makes sense...

– porthfind

2015/10/26 at 19:22
@ramaral works up to Log. d("Expan","get->"+products.get(0). getNomeProduct());

– porthfind

2015/10/26 at 19:22
Take off the i of add in categoria_header.add(i,produtos.get(j).getNomeProducto());

– ramaral

2015/10/26 at 19:27
@ramaral, if I take the i, I’ll be adding my products to all categories and I don’t want that, I want to add the commodities to the categories they correspond to. I don’t know if I made myself clear..

– porthfind

2015/10/26 at 19:38
The first category has products?

– ramaral

2015/10/26 at 19:55
@ramaral, No..

– porthfind

2015/10/26 at 19:57

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by ramaral • **44,197** points · Answer 1 · 2015-10-26T20:15:40+00:00

The mistake happens when you do the add() on the list categoria_header. If the first category has no products nothing is placed on the list, the i is increased, passes to 1, when trying to add i = 1 makes a mistake because i shall not be greater than size of the list.

If I understand what you want to do, alter the code like this:

LinkedHashMap <String, List<String>> expandableListDetail2 = new LinkedHashMap<String, List<String>>();

    int i=0;
    List<Producto> produtos;
    Database db = new Database(context);
    List<Categorias> categorias;

    categorias = db.getAllCategorias();

    for (i=0; i<categorias.size(); i++){

        List<String> categoria_header = new ArrayList<String>();

        produtos = db.getAllProductos(categorias.get(i).toString());

       for(int j=0;j<produtos.size();j++) {
           Log.d("Expandable","categoria->"+categorias.get(i).toString());
           Log.d("Expan","get->"+produtos.get(0).getNomeProducto());
           categoria_header.add(produtos.get(j).getNomeProducto());
       }

        expandableListDetail2.put(categorias.get(i).toString(), categoria_header);

    }
}

The Hashmap expandableListDetail2 should receive a new list categoria_header for each category. Therefore a new object should be created within the cycle for(i=0; i<categorias.size(); i++)

_{Note: I think I should change the name categoria_header for categoriaProducts}