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For the Operating System, a process regardless of its state is a running program?
The question of proof was true or phony. I chose phony, but the answer was wrong. Can anyone explain to me why?
1 answer
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In multitasking systems, only when a process has its instructions interpreted and executed by the processor is its state called 'under execution'.
There are several possible states - 'standby, 'locked' and 'created', among others. None of these is considered 'under execution'.
From this point of view, it seems to me that your teacher is correct.
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I think the question has been misspelled. It could be better explored by your teacher, such as whether the OS in question is mono or multi thread.
– Weslley Tavares
because it was right?
– rray
puts a
>in front of the To the system, shows better.– rray
Because the definition of processes are tasks in execution, that is, it needs to take on the state of "PERFORMING" to take on such a role.
– Weslley Tavares
Analyzing the answer of @Onosendai, I believe that the question was also poorly formulated. But, anyway, it is up to the teacher and the class.
– Weslley Tavares
@rray I see no reason to do this, strictly speaking the
>is for citations.– bfavaretto
I think we’re missing a couple of commas. I think the question is, "For the Operating System, a process, regardless of its state, is a running program?"
– Franchesco
@bfavaretto, it seemed appropriate to me because it was something external, IE, it was not the OP who asked the question if there is something wrong was not on his part, so I suggested, if it is not applicable in this context has no problem :)
– rray
I hadn’t thought of it that way, @rray. It actually works both ways.
– bfavaretto
I copied the question of proof. It was written that way.
– ZERO