How to convert seconds to "Hour:Minute:Second" format?

Question

How can I convert a value in seconds to a format of 'hours:minutes:seconds'.

Example: 685 converted to 00:11:25

As I can do?

Answer 1

You can use the function gmdate():

echo gmdate("H:i:s", 685);

_{Refers to that answer soen}

Answer 2

You can go splitting seconds to find hours and minutes:

$total = 685;
$horas = floor($total / 3600);
$minutos = floor(($total - ($horas * 3600)) / 60);
$segundos = floor($total % 60);
echo $horas . ":" . $minutos . ":" . $segundos;

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

Answer 3

Beyond calculation, already passed by Maniero:

$horas = floor($total / 3600);
$minutos = floor(($total - ($horas * 3600)) / 60);
$segundos = floor($total % 60);

It is important to remember that if one of the numbers is smaller than 10, then a format like this can come out:

1:4:31

When the expected should be:

01:04:31

For this you can use str_pad or sprintf (this last suggestion from Wallace), as I suggested in /a/51828/3635:

<?php
function getFullHour($input) {
    $seconds = intval($input); //Converte para inteiro

    $negative = $seconds < 0; //Verifica se é um valor negativo

    if ($negative) {
        $seconds = -$seconds; //Converte o negativo para positivo para poder fazer os calculos
    }

    $hours = floor($seconds / 3600);
    $mins = floor(($seconds - ($hours * 3600)) / 60);
    $secs = floor($seconds % 60);

    $sign = $negative ? '-' : ''; //Adiciona o sinal de negativo se necessário

    return $sign . sprintf('%02d:%02d:%02d', $hours, $mins, $secs);
}

echo getFullHour(685), PHP_EOL; //00:11:25

echo getFullHour(140801), PHP_EOL; //39:06:41
echo getFullHour(100800), PHP_EOL; //28:00:00

echo getFullHour(-140801), PHP_EOL; //-39:06:41
echo getFullHour(-100800), PHP_EOL; //-28:00:00

See an example in repl.it: https://repl.it/@inphinit/Show-hours-over-24-hours-and-Negative-hours

Answer 4

#include <stdio.h>

int main()
{
    float time, hour, min, sec;
    scanf("%f", &time);
    hour = time / 3600;
    min = (((time/3600) - (int)hour) * 3600)/60;
    sec = (min - (int)min) * 60; 
    printf("%.0f\n%.0f\n%.0f\n", hour, min, sec);
    return 0;
    
}