Problem configuring spring data jpa project with Hsqldb

Question

I am trying to set up a project example using Spring Data JPA with Hsqldb

I made the class I would be model, to interface repository and a main class to run.

I didn’t create the bank because I have a doubt if Spring created it for me automatically as Hibernate has this option.

Personal class

package data.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Table;

import org.springframework.data.jpa.domain.AbstractPersistable;

@Entity
@Table(name = "pessoa")
public class Pessoa extends AbstractPersistable<Long> {

    @Column(name = "nome", nullable = false, length = 25, unique = false)
    private String nome;

    @Column(name = "sobrenome", nullable = false, length = 25, unique = false)
    private String sobrenome;

    @Column(name = "idade", nullable = false, unique = false)
    private Integer idade;

    public String getNome() {
        return nome;
    }

    public void setNome(String nome) {
        this.nome = nome;
    }

    public String getSobrenome() {
        return sobrenome;
    }

    public void setSobrenome(String sobrenome) {
        this.sobrenome = sobrenome;
    }

    public Integer getIdade() {
        return idade;
    }

    public void setIdade(Integer idade) {
        this.idade = idade;
    }

}

Repository class

package data.repository;

import org.springframework.data.jpa.repository.JpaRepository;

import data.model.Pessoa;

public interface PessoaRepository extends JpaRepository<Pessoa, Long> {

}

Test Class

package data.teste;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;

import data.repository.PessoaRepository;

@Component
public class Test {

    @Autowired
    private PessoaRepository pessoaRepository;

    public PessoaRepository getPessoaRepository() {
        return pessoaRepository;
    }

    public void setPessoaRepository(PessoaRepository pessoaRepository) {
        this.pessoaRepository = pessoaRepository;
    }

}

When running main, it opens a window of the Eclipse to select a class within a list of some classes of the Hsqldb. So I’m confused about what might be.

My xml configuration file Spring.

Xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:jdbc="http://www.springframework.org/schema/jdbc" 
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:jpa="http://www.springframework.org/schema/data/jpa"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
                        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd
                        http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc-4.0.xsd
                        http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa-1.3.xsd">

    <context:annotation-config/>

    <jpa:repositories base-package="data.repository" query-lookup-strategy="create-if-not-found"/>

    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
                <property name="showSql" value="true"/>
                <property name="generteDdl" value="true"/>
            </bean>
        </property>
        <property name="persistenceUnitName" value="persistenceUnitName"/>
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory"/>
        <property name="jpaDialect">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaDialect"/>
        </property>
    </bean>

</beans>

Answer 1

Hello!

This may occur because the main method signature is incorrect or because the class containing the main method is not defined in Class-Path.

• Signature of the correct main method:

   public static void main(String[] args) { ... }
  

• You can run the main method by pressing with the right click on top of the method, and inside the menu Run As and click on Java Application.

• It is also possible create a configuration through the menu of the Eclipse Run >> Run Configurations...

Note: It will be necessary load the Spring context inside the main to be able to access the Beans.

Abs!