Bowling score in C;

Question

I’m a beginner in C And I’m having problems in an exercise, I can’t see a way to solve it. Following:

In each stage the player has 2 balls with which to knock down 10 pins. The stage ends when: the player knocks down the 10 pins or the player uses the 2 balls.

i = bola1;
j = bola2;

pontuação
    1 – STRIKE   se i = 10 (a 2a bola não é usada); 
    2 – SPARE    se i < 10, mas  i + j = 10;
    3 – MISS       se i + j < 10;
Valor pontuação
STRIKE - 10 + números de pinos que o jogador derrubar com as duas bolas  seguintes.  
SPARE - 10 + número de pinos derrubados com a próxima bola   
MISS - i + j


a) Leia uma seqüência de números inteiros que descreve  um jogo completo. O i-ésimo termo da sequência é o número de pinos derrubados pela i-ésima bola. Qual será o tamanho máximo da seqüência? 
b) Identifique a quantidade de pinos derrubados por cada etapa e classifique como STRIKE, SPARE ou MISS. 
c) Calcule o número de pontos por etapa 
d) Calcule o total de pontos no jogo 
e) Imprima os resultados   

Numero de exemplo;
    1o jogo: 10, 9, 1, 6, 3, 7, 0, 8, 2, 0, 8, 2, 0, 8, 2, 0, 8, 1, 0, 9, 1;   
    2o jogo: 9, 1, 0, 10, 10, 10, 6, 2, 7, 3, 8, 2, 10, 9, 0, 9, 1, 2; 
    3o jogo: 10, 9, 0, 8, 2, 10, 10, 7, 3, 4, 6, 10, 9, 1, 10, 7, 3;

Well, I tried to use one for to check the value of each vector position, so far so good, my problem is to compare the next two values if the first is not a Strike.

main() {
    int game1[20] = {10, 9, 1, 6, 3, 7, 0, 8, 2, 0, 8, 2, 0, 8, 2, 0, 8, 10, 9, 1};
    int game2[18] = {9, 1, 0, 10, 10, 10, 6, 2, 7, 3, 8, 2, 10, 9, 0, 9, 1, 2};
    int game3[17] = {10, 9, 0, 8, 2, 10, 10, 7, 3, 4, 6, 10, 9, 1, 10, 7, 3};
    int i, j;

    for(i=0; i<20; i++) {
        for(j=0; j<20; j++) {
            if(game1[i] == 10) {
                printf("Strike");
            }
        }
    }   
} 

This is the code I started to do, but my doubt is more in the logical part, how to compare the value of i and j to know if it is a Strike, Spare or Miss;

Answer 1

For him to walk more than a house just increase the i when it’s not "STRIKE".

#include <stdio.h>
#define JOGADAS 20

int main(void) {
    int game1[JOGADAS] = {10, 9, 1, 6, 3, 7, 0, 8, 2, 0, 8, 2, 0, 8, 2, 0, 8, 10, 9, 1};
    //int game2[18] = {9, 1, 0, 10, 10, 10, 6, 2, 7, 3, 8, 2, 10, 9, 0, 9, 1, 2};
    //int game3[17] = {10, 9, 0, 8, 2, 10, 10, 7, 3, 4, 6, 10, 9, 1, 10, 7, 3};
    int i;

    for(i=0; i<JOGADAS; i++) {
        if(game1[i] == 10) {
            printf("STRIKE\n");
        }
        else if (game1[i]+game1[i+1] == 10) {
            printf("SPARE\n");
            i++; //avança mais uma casa para o próximo jogo.
        }
        else {
            printf("MISS\n");
            i++; //avança mais uma casa para o próximo jogo.
        }

    }
    return 0;
}

Behold here to work.

Answer 2

Dude, you should review the structure you used to store the dice for each move. The way the data is being saved, you can’t know which round the score refers to unless you do a full execution of the algorithm, which makes it extremely inefficient (after all save the result of the plays serves exactly so you do not need to do everything again).

I recommend that you create a custom structure, for example:

struct rodada{
    int jogada1;
    int jogada2;
};

struct rodada game1[20];

That way the information about the outcome of the i-th move will be only one instruction away. I mean, you just do a resultado = game1[10].jogada1; to know if it was a strike or not. No need to read ALL MOVES to the tenth for such simple information.

I also recommend setting some invalid value (such as an "x" or a boolean variable) in the second move to signal that there was a strike in the round.

Obs: Sorry if there’s some error in the code.
Obs2: You could also add another variable in the struct to keep the partial score of each round.