How to apply multiple image upload

Question

Hello I have this code that generates in the case of multiple adders with everything I’m not sure how to make an image upload code to upload all the images that are placed in FILE of the field of filing cabinet[ ] someone could help me supplement the code .

In case I need the code to upload to the medium folder, apply resizing, logo tag and Upe all images and add the values of the image in arquivo='".$archiveImage[$values]."' also since thank you who can help me.

Below is the code I did with everything without the image upload code. I’m still starting my course in PHP and there’s a lot I don’t know how to do.

I only managed to do only in case the repeat code using the for and add direct values to database.

index php.

<form id="form1" name="form1" method="post" action="multiplicar.php">
  Coloque aqui o numero de episodios que vc ira adicionar 
  <label>
    <input type="text" name="numeros" id="numeros" style="width:20px;" />

  </label>
  <label>
    <input type="submit" name="button" id="Gerar" value="Gerar" />
  </label>
</form>

multiply.php

<form id="form1" enctype="multipart/form-data" name="form1" method="post" action="salvar.php">
    <?php
    $valor = $_POST["numeros"];
    for ($repeticao = 1; $repeticao <= $valor; $repeticao++) { ?>
      <label>
       Nome  <input name="categorias[]" type="text" id="numero" value="" size="10" />  Tipos  <input name="tipos[]" type="text" id="tipos" value="" size="10" /></br>
       Imagem <input name="arquivo[]" type="file" id="arquivo[]" style="border:0px; width:249px;box-shadow: 0px 0px 2px #5B5B5B;border-radius:0px; font-family:'Arial'; font-size:14px; padding-left:0px; padding-right:0px;"/> 
      </label>
    <? }  ?>
    <input type="submit" name="button" id="button" value="Enviar" />
    </form>

save php.

<?php   
    $categoria = $_POST["categorias"];   
    $tipo = $_POST["tipos"];   
    $arquivoImagem = $_POST["arquivo"];   
    $numeracao = 1;
    foreach($categoria as $valores => $maiorIgual) {


    // Faz a inserção dos dados na MYSQL
    $sql = "INSERT INTO `medias` SET `cat`='".$categoria[$valores]."', `tipos`='".$tipo[$valores]."', `arquivo`='".$arquivoImagem[$valores]."'";
    $consulta = mysql_query($sql);
    if($consulta) {
    echo'<center>';
    echo " Item ".$numeracao++." Cadastrado com Sucesso<br/>";
    }else{
    echo " Item ".$numeracao++." Erro ao cadastrar<br/>";
    echo'</center>';
    }
    } ?>

Answer 1

Do not use $arquivoImagem = $_POST["arquivo"]; use $arquivoImagem = $_FILES["arquivo"];

• $_FILES['userfile']['name']

  The original file name on the client’s machine.

• $_FILES['userfile']['type']

  The mime type of the file, if the browser provides this information. An example could be image/gif. The mime type however is not checked by PHP so do not consider that this value will be granted.

• $_FILES['userfile']['size']

  The size, in bytes, of the submitted file.

• $_FILES['userfile']['tmp_name']

  The temporary name with which the uploaded file was stored on the server.

• $_FILES['userfile']['error']

  The error code associated with this file upload.

Note: I really don’t see why to use foreach if the array is not associative.

Example:

foreach ($categoria as $valores => $maiorIgual) {
    $name = $_FILES['file'][$valores]['name'];
    $tmp_name = $_FILES['file'][$valores]['tmp_name'];

    $error = $_FILES['file'][$valores]['error'];
    if ($error !== UPLOAD_ERR_OK) {
        echo 'Erro ao fazer o upload de:', $name, ' / Erro: ', $error;
    } elseif (move_uploaded_file($tmp_name, $location . $name)) {
        $sql = "INSERT INTO `medias` SET `cat`='".$categoria[$valores]."', `tipos`='".$tipo[$valores]."', `arquivo`='".$arquivoImagem[$valores]."'";
        //Resto do seu código  
    }
}

I recommend that if you do not use associative arrays, use for normal instead of foreach

$categoria = $_POST["categorias"];   
$tipo = $_POST["tipos"];   
$arquivoImagem = $_POST["arquivo"];

$total = count($arquivoImagem);

if ($total !== count($tipo) || $total !== count($categoria)) {
    //Adicionei este if só como segurança com problemas no formulário
    echo 'Quantidade de itens é invalida';
} else {
    for ($i = 0; $i < $total; $i++) {
        $name = $_FILES['file'][$i]['name'];
        $tmp_name = $_FILES['file'][$i]['tmp_name'];

        $error = $_FILES['file'][$i]['error'];
        if ($error !== UPLOAD_ERR_OK) {
            echo 'Erro ao fazer o upload de:', $name, ' / Erro: ', $error;
        } elseif (move_uploaded_file($tmp_name, $location . $name)) {
            $sql = "INSERT INTO `medias` SET `cat`='".$categoria[$i]."', `tipos`='".$tipo[$i]."', `arquivo`='".$arquivoImagem[$i]."'";
            //Resto do seu código  
        }
    }
}

To better understand the use of HTML arrays: http://php.net/manual/en/faq.html.php#Faq.html.arrays