How to create array dynamically?

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3

I would like to create a array dynamically, I tried this way:

$zt = array();
    $zt = ($p_p[0] => $_p_p[1]);
    print_r($zt);

$p_p is a array, where index 0 is the name, and index 1 is the value, 2 name, 3 value..

$p_p is configured like this, but unfortunately gives error in line $zt:

Parse error: syntax error, Unexpected '=>'

If I do so:

$zt = ($p_p[0]);

no mistake, but the index is "0", I needed it was in fact the name, since I will pass this array $zt for POST as if they were fields of a form.

php array
  • 1

    Look, I found the solution, but I didn’t find it logical. I declared as array $zt, like this: $zt = array();, then I hoped that what $zt gets behaves like array, but I needed to change for that: array($p_p[0] => $_p_p[1]);, that is, I informed that it was array(again) what I put inside.

  • 1

    You had to declare again that the $zt is an array because you are overwriting the variable $zt.

  • perfect! thanks

2 answers

7

From what I understand you want $p_p[0] be the key and $p_p[1] the value, then:

$zt = array();
$zt[$p_p[0]] = $p_p[1];
print_r($zt);

  • Luiz, thank you for the answer, I did not know that an index could receive a value like this!

2

If you want to create a simple array (non-associative):

$zt = array();
$zt[] = $p_p[0] => $_p_p[1];

If you want to create an associative array 

$zt = array();
$zt[$p_p[0]] = $p_p[0] => $_p_p[1];

The difference is that one assigns the index automatically (numerical) and the second variant can have an index assigned (string).

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