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Data n, print the value of
Sn = 1/n + 2/(n-1) + 3/(n-2) + ... + n.
This is what I tried to do:
n =2
soma =1
for i in range(1,n+1):
if n>i:
soma+=i/n + i/(n-1)
But it only works when n=2. Someone could help?
0No answers
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I’m sorry for the ignorance, but this sequence is strange. It implies that the values will eventually converge on
n, but in fact they will converge onn+1/(n-n), in which you will get a division error by 0. This sequence is right?– Andre
@Andre withdrew from an exercise; https://www.ime.usp.br/~Cris/lessons/08_1_110/abril.html
– Ed S
@Andre pulled from one exercise - Problem 10.1:; https://www.ime.usp.br/~Cris/lessons/08_1_110/abril.html
– Ed S
Well, in the exercise itself has an example of C implementation, which converted to Python would be thus, I guess you can use it as a reference, it’s your tie
forthat is doing more thing.– Andre
@Andre did not understand (i+1)/(n-i)
– Ed S
It’s the general term of your series
– Woss
@Woss really did not understand how this general term was arrived at
– Ed S