Python script run every 1 second for 3 hours in a row

Question

I need to run a Python script every 1 second for 3-4 hours a day.

This my script updates the data in a table, performs some calculations and takes an action if the calculation rule determines.

Although simple, I could not find something on the forums that could help me to have a direction.

I’d like some suggestions on how I could do that.

Answer 1

In my view it has two forms:

1. Internal loop in the script

You can put your code inside a loop with a timer like this:

import time

while True:
    ... seu script aqui
    time.sleep(1)

2. You could use the "watch" command from linux to run the command from 1 in 1 seconds, for example:

$ watch -n 1 python meuscript.py

Answer 2

#https://pypi.org/project/APScheduler/

Pip install apscheduler

Try scheduled (scheduled scheduling)

from apscheduler.schedulers.background import BackgroundScheduler

 scheduler = BackgroundScheduler()
    scheduler.add_job(train_model, 'interval', hours=3)
    scheduler.start()

If you want to create a medium without api:

import time
import random 

def infinito():
  print("teste")

while True:
    try:
        if infinito() == 1:
            break
    except:
        parada = random.randrange(1, 10)#por um tempo aleatório entre 1-10 ira parar 
        time.sleep(int(parada))
        #time.sleep( parada * 60 )      #a cada minuto ira entrar em um lopp infinito
        pass

no 60 exchange for minutes to hour or days