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Hello, I’m trying to do an exercise involving random numbers with the following code:
int sorteio1 = (int)(Math.random() * 6) +1;
int sorteio2 = (int)(Math.random() * 6) +1;
int sorteio3 = (int)(Math.random() * 6) +1;
int sorteio_usuario = (int)(Math.random() * 6) +1;
However, I am finding the following difficulty: the variables sorteio1, sorteio2, sorteio3, cannot have the same value... Is there any way to do this?
I even thought about taking intervals, for example, the draw goes from 1 to 2, the draw goes from 3 to 4 and the draw goes from 5 to 6. However, I could not find ways to apply this draw by interval in the code above. Maybe using a for each variable draw would work, but I feel like maybe it was a scam...
Is there any way to do that WITHOUT use array, vector, list etc?
Hello Victor, can solve easily with "recursiveness". Run the sorteio1, then run the sorteio2 and compare if it is equal to sorteio1, if yes do a recursion to run again, until the value is different (probably in the second attempt it will be already, but an infinite loop solves, it can also be a recursion method). Now run sorteio3 and compare the sorteio1 and sorteio2, with an IF check if 3 is equal to 1 or 2, if it is equal to one of them, make a recursion (can be with loop or a method that calls itself), when it is different close the loop.
– Guilherme Nascimento
Still if it is to have a dynamic number of draws use A vector would solve easily
private ArrayList<Integer> sorteios = new ArrayList<Integer>();, it would add the results to:for (int i = 1; i <= numSorteios; i++) { sortear.add(sortear()); }, and in the method (no need for a method, but preferred to separate) checks whether the number already exists insorteioswith a simple IF usingArrayList.contains()thusint sortear() { int novo = (int) (Math.random() * 6) + 1; if (sorteios.contains(novo)) { return sortear(); /*se já existir sorteia novamente*/ } else { return novo; } }– Guilherme Nascimento