Substituting and displaying parameters in PHP

Question

I’m creating a coder, a personal project to apply knowledge and learn more.

The coding part is working, but the decoding part isn’t. I execute and nothing appears.

Could someone help me find the problem?

<div id="area">
    <form method="POST" action="resultado.php">
        <fieldset><label> <h2 class="a"> Escolha uma opção: </h2> </label>
            <input type="radio" name="condiçao" id="codificar" value="codificar"> <label for="codificar">Codificar</label>
            <input type="radio" name="condiçao" id="decodificar" value="decodificar"> <label for="decodificar">Decodificar</label>
        </fieldset>
        <label> <h2 class="a">Digite o texto:</h2> </label>
        <textarea name= "txt" class="cod" cols="100%" rows="20" > </textarea>
        <br>
        <button> ENVIAR </button>
    </form>
    </div>
    
    <?php
    echo "<h2> Resultado: </h2>";
    $condiçao = isset($_POST["condiçao"])?$_POST["condiçao"]:" ";
    $txt = isset($_POST["txt"])? trim($_POST["txt"]):" ";
    //conta
    $cont = str_word_count($txt);
    //divide
    $v= explode(" ", $txt);
    //junta
    //inicio contador
    $i = 0;
    while ($i>$cont) {
        if($v[$i] == "21UO4UTYEP"){
            echo "A";
        }    
        elseif ($v[$i] == "IPDQXS1QGL") {
            echo "B";
        }
        $i++;
    }
    ?>

Answer 1

You assign the value of $cont equal to the number of words and the value $i equal to 0, then you say while $i is greater than $cont.

Your code never enters the loop, $i will never be bigger than the counter.

Reverses.

while($i < $cont){}