How to call two mysql tables in the same php page?

Question

How to call two mysql tables in the same php page?

Asked 9 years, 5 months ago

Viewed 1,253 times

0

I’m new to programming for the web, and I’m having a hard time with this. I’m developing an advertising site and I need to call more than one table on the page.

I made 3 Div’s advertising: Main, Free and General.

I can only show the advertisements of the main, the free and general I can not.

As I’m calling the principal:

<?php
while ($dados=mysql_fetch_array($res))
{
?>

<?php echo $dados['site']?> <br>
<?php echo $dados['descricao']?> <br>
<img src="Painel/fotos/<?php echo $dados['foto']?> /><br>

<?php }?>

I’m trying to do the same thing for the other two divs and I can’t help myself?

2

Displays the example with two and with the SQL query.

– Jorge B.

2015/01/14 at 18:04
Explain what "I can’t" is. Is it wrong? Which one? An important detail, especially for you who are a beginner, is that mysql_* functions have been obsolete since PHP 5.5. Use Mysqli or PDO. See more here: http://www.ultimatephp.com.br/php-por-que-nao-utilizar-funcoes-mysql

– Beraldo

2015/01/14 at 18:06
To 'combine' tables in sql you need a join or union.

– rray

2015/01/14 at 18:07
I’m taking the data from the group like this: <?php include ("connected.php"); $sql="select * from main"; $res= mysql_query ($sql); ? > .

– Mateuslapa

2015/01/14 at 18:10
Try it with $sql1, $sql2 and $sql3 and $res1 $res2 and $res3.

– Jorge B.

2015/01/14 at 18:19
Blz, I’ll try, thank you

– Mateuslapa

2015/01/14 at 18:20

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1 answer

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by Nelson Teixeira • **1,408** points · Answer 1 · 2015-01-14T18:05:18+00:00

Just copy this code to the other div, with a mysql_query and a mysql_fetch_array for each one. With mysql_query you got the data for this right ? then.. get the data for each table in the other Ivs

Edit:

that is to say:

<?php 
    include ("conexao.php"); 

    $sql="select * from principal"; $res= mysql_query ($sql); 
    while ($dados=mysql_fetch_array($res))
    {
        echo $dados['site'] . "<br>";
        echo $dados['descricao'] . "<br>";
?>
<img src="Painel/fotos/<?php echo $dados['foto']?> /><br>

<?php } ?>
    <br><br>
<?php 
    $sql="select * from gratuitas"; $res= mysql_query ($sql);
    while ($dados=mysql_fetch_array($res))
    {
        echo $dados['site'] . "<br>";
        echo $dados['descricao'] . "<br>";
        ?>
    <img src="Painel/fotos/<?php echo $dados['foto']?> /><br>

<?php } ?>
    <br><br>
<?php 

    $sql="select * from geral"; $res= mysql_query ($sql); 
    while ($dados=mysql_fetch_array($res))
    {
        echo $dados['site'] . "<br>";
        echo $dados['descricao'] . "<br>";
    ?>
    <img src="Painel/fotos/<?php echo $dados['foto']?> /><br>

<?php }
?>

I have not tested this code, there may be some syntax error. Correct if there is. The code above is to give an idea of what I mean.