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I’m trying to make a footer on the site with access to the bank to show the logged in user, but when soon gives this error, I already searched and could not solve.
my footer:
<?php
if (!isset($_SESSION)) {
session_start();
}
if ((!isset($_SESSION['usuario']) == TRUE) && (!isset($_SESSION['senha']) == TRUE) && (!isset($_SESSION['id']) == TRUE) && (!isset($_SESSION['perfil']) == TRUE) && (!isset($_SESSION['nome']) == TRUE)) {
session_unset();
session_destroy();
header('location: login.php');
}
include './conexao.php';
$nome = $_SESSION['nome'];
$id = $_SESSION['id'];
$select = "SELECT pu.descricao "
. "FROM perfil_usuario pu "
. "INNER JOIN login lo ON lo.perfil = pu.id "
. "WHERE lo.id = '$id'";
$result = mysqli_query($conexao, $select);
$linha = mysqli_fetch_array($result);
?>
<div id="footer">
<label id="label"><?php echo $nome . ' - ' . $linha['descricao'] ?></label>
</div>
I’m calling it that at the end of my html content:
<?php include './rodape.php'?>
If I take the snippet from include './connected.php'; it works without error.
Such a.php connection must have some space or other and must also have headers. See: https://answall.com/a/18812/3635
– Guilherme Nascimento
Exactly, the connection has a
headerwithcharset, how do I put thecharsetnow?– Ari
Put before the space that should exist within your.php connection, see: https://answall.com/a/18812/3635
– Guilherme Nascimento
the session and headers must be started before any output from php to the screen. if you have any print or even a space before that, this error will be displayed.
– Jasar Orion