How do I remove characters from even positions in a string?

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I have a string and I want to remove from it only the characters in even positions

python-3.x

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1 answer

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You can use a little trick list:

>>> a = "01234567"
>>> a[::2]
'0246'
>>> a[1::2]
'1357'

I put the 2 options because I don’t know if you consider the first position as odd or as even (since it is a[0])

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