0
Good morning.
I have the following code in a class that works perfectly well when I print inside it. Now when access through another class file presents me error. Below demonstrate class that works :
import os
class WspApplication:
ws_listdir = os.listdir('../application/controllers')
This class works when I print inside it.
It only shows the error below when I try to access it in another class:
ws_listdir = os.listdir('../application/controllers') Filenotfounderror: [Errno 2] No such file or directory: '.. /application/controllers'
Below follows the other class :
from syscore.wsp_application import WspApplication
class WspProtected:
def wsm_dir(ws_path):
ws_root = WspApplication.ws_listdir
if ws_path == ws_root:
return 'Info. . .'.encode('utf-8')
You can disregard the path parameter in the analysis it works !
these two classes are in the same directory and/or have the same access permissions?
– Giovana Morais
yes and are without permissions.
– João Carlos
../application/controllers
this location is right? ta in project folder?– Tmilitino
Yes, the classes are in the same directory already the path ( ../ application / controllers ) that I want to access are in another directory as above, but in the same root.
– João Carlos