Access out-of-loop variable for

Question

As access to variable cookies out of the loop?

cookies = []
for i in get_cookies(url):
   cookies = '='.join(i) + '; '
print(cookies)

Is just returning this:

personalization_id="v1_8yKL+7c5RUQ+HHELlnh5dw==";

I need you to return everyone else in one line, when I give print(i), is returning:

('_twitter_sess', 'BAh7CSIKZmxhc2hJQzonQWN0aW9uQ29udHJvbGxlcjo6Rmxhc2g6OkZsYXNo%250ASGFzaHsABjoKQHVzZWR7ADoPY3JlYXRlZF9hdGwrCDzJKCprAToMY3NyZl9p%250AZCIlMDY3NjhlNWQ2NzIwZWIzOWFhOGY4YmNjM2QyZTJlODY6B2lkIiU3OTY2%250AMmM1YjYzYmViYTgxYmZhNDM5OWVjYzJiMzU3Mg%253D%253D--1986635940f2d9bf0f775422f9999122b0279d8c')('ct0', '94d313ad03ce413f521761c16b4bfb63')('guest_id', 'v1%3A155978044447406891')('personalization_id', '"v1_8yKL+7c5RUQ+HHELlnh5dw=="')

I need you to stay like this:

_twitter_sess=BAh...; ct0=123... so on and so forth

Answer 1

Your code:

cookies = []
for i in get_cookies(url):
   cookies = '='.join(i) + '; '
print(cookies)

You defined cookies as a list, but wants the result to be a string; within the repeat loop you are overriding the value of cookies, that is, the previous value will always be lost. So, after finishing the loop, only the last cookie will be in cookies.

To fix it you 1) correctly starts the variable cookies and 2) uses concatenation instead of assignment within the loop.

cookies = ''
for i in get_cookies(url):
   cookies += '='.join(i) + '; '
print(cookies)

But it’s Python, you don’t have to do it all by hand, just use the tools that language gives you:

cookies = ';'.join(f'{name}: {value}' for name, value in get_cookies(url))