How to check the Code status of an ajax request

Question

I have a very simple AJAX request. But I wonder if you can read the status code returned within the method done. More or less like below:

$('#form-aluno').submit(() => {
    let data = $('#form-aluno').serialize();


    const register = $.ajax({
        method: "post",
        url: "/alunos/register/save",
        dataType: "json",
        data: data
    })

    register.done((e) => {
        console.log(e.statusCode) //tem como fazer algo do tipo ou similar ?
    })


    return false;
})

Answer 1

I was able to solve the problem in question. I’ll leave the answer here in case anyone has any doubts

solved using the third callback parameter of the ajax done function as below:

register.done((e, status, code) => {
    console.log(code.status)
})