How to ignore the default Model $with in Laravel (Eloquent ORM)

Question

I have a model with with already predefined calling some other models.

public $with = ["itens", "filial", "cliente", "status", "produtos", "servicos",
  "composicoes", "execucoes", "tipo", "vendedor", "locacoes"];

want to ignore the object "products", how can I do this?

Answer 1

Develop a Scope to remove from the early interface the item or items:

public function scopeNoEagerLoadsExcept($query, array $items)
{
    if (count($items) == 0)
    {
        return $query;
    }

    $eagerLoads = $this->getEagerLoads();
    $keysEagerLoads = array_keys($eagerLoads);
    $with = array();
    foreach ($keysEagerLoads as $key)
    {
        if (!in_array($key, $items))
        {
            $with[$key] = $eagerLoads[$key];
        }
    }
    $query->setEagerLoads($with);
    return $query;
}

in that method makes a check if the item is inside the charge key in advance and removes the item in that Builder created, and it is worth remembering that after this result materialization the load goes back to being as before with all the configured relations that is very useful for the next researches where they need all the relations.

^{Example of use:}

 ItemsProduct::noEagerLoadsExcept(['produtos'])->get();

^Reading

• What good is a Cope in the Laravel?
• Select model methods in the Laravel controller index method?
• Relationship of Laravel Relationship
• Disable Eager Relations

^Tip

If you want this model do not load the configured relations, ie no relation, use the method setEagerLoads([]), example:

ItemsProduct::setEagerLoads([])->get();