How to increment variables

Question

In the code below my variable y asks the user to enter values until y reaches 10, I store the variable x and currently the last information typed is stored (which shows at the end of the code) what I would like to know is how to make an "increment" in var x, storing the information typed in X1, x2, X3. up to X10, as with Y.

import java.util.Scanner;
    public class SEP_06_exe2_p1{
        public static void main(String args[]){
             int x;
             int y = 1;
             do{         
                 Scanner input = new Scanner(System.in);
                 System.out.print("Digite o " + y + "º valor: ");
                 x = input.nextInt();
                 y = ++y; //incrementa 1 no y 
             }while( y <= 10);
             System.out.print(x);
        }
    }

Answer 1

Basically what you need to do is use a array (java tutorial and class documentation). It is a variable that stores several values (a collection of values). Hence you access each individual value through its index. It would be something more or less like this (I did not test, I do not know if what you did is working, I put to illustrate what you need to use):

import java.util.Scanner;
public class SEP_06_exe2_p1 {
    public static void main(String args[]) {
        int[] x = new int[10];
        int y = 0;
        Scanner input = new Scanner(System.in);
        do {         
            System.out.print("Digite o " + (y + 1) + "º valor: ");
            x[y] = input.nextInt();
            y++; //incrementa 1 no y <== estava errado veja nota abaixo
        } while (y < 10);
        y = 0;
        do {         
            System.out.println(x[y]);
            y++;
        } while (y < 10);
    }
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

The operator ++ generates side effect, that is, it modifies the state of the variable itself, so you do not need to assign the result to a variable. y++ is the same thing as saying y += 1 that the same as saying y = y + 1. There’s a way to simplify this even more, but since you’re starting out and there are controversies if this simplification is good, I won’t quote you.

Arrays always start from scratch. So I changed the initial value of y and the comparison of while to finish before reaching the 10, ie it goes from 0 to 9.

You could use a flow control for in this case, it simplifies a little. But take one step at a time.

Answer 2

You can try using the code below, which will perform a sum(guardaX) of the values of x as with the variable y:

import java.util.Scanner;
    public class SEP_06_exe2_p1{
        public static void main(String args[]){
             int x;
             int guardaX = 0;
             int y = 1;
             do{         
                 Scanner input = new Scanner(System.in);
                 System.out.print("Digite o " + y + "º valor: ");
                 x = input.nextInt();
                 guardaX = x + guardaX;
                 y = ++y; //incrementa 1 no y 
             }while( y <= 10);
             System.out.println(x);
             System.out.println(guardaX);
        }
   }