Doesn’t show the right way out

Question

I believe I may be the result of my ordination that is influencing the output, eg if it was 6 8 10 should show RECTANGULAR TRIANGLE but is showing ACUTANGULO TRIANGLE.

The code I made at the end of the statement

Read 3 decimal numbers A, B and C and ordinances in descending order, from mode that side A represents the largest of the 3 sides. Next, determine the type of triangle these three sides form, based on the following cases, always writing an appropriate message:

if A B+C, display message: NO TRIANGLE

if A 2 = B 2 + C 2, display the message: RECTANGULAR TRIANGLE

if A 2 > B 2 + C 2, display message: OBTUSE TRIANGLE

if A 2 < B 2 + C 2, display message: ACUTANGULO TRIANGLE

if the three sides are equal, display the message: TRIANGLE EQUILATERAL

if only two sides are equal, display the message: ISOSCELE TRIANGLE

Ex Inputs (A, B, C) Expected output 7 5 7
ACUTANGULO ISOSCELE TRIANGLE 6 6 10 OBTUSANGULE TRIANGLE ISOSCELE TRIANGLE

6 6 ACUTANGULO TRIANGLE EQUILATERAL TRIANGLE

5 7 2 NO TRIANGLE SHAPE

6 8 10 RECTANGULAR TRIANGLE

Code

public class Ex18 {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        double a,b,c,maior;

        System.out.printf("Digite o valor de A: ");
        a=sc.nextDouble();
        System.out.printf("Digite o valor de B: ");
        b=sc.nextDouble();
        System.out.printf("Digite o valor de C: ");
        c=sc.nextDouble();


        if(a > b){
          maior = a;
          a = b;
          b = maior;
        }if(b > c){
          maior = b;
          b = c;
          c = maior;
        }
        if(a>= c+b){
           System.out.println("NAO FORMA TRIANGULO");

        }else if((a*a) == (b*b)+(c*c)){
            System.out.println("TRIANGULO RETANGULO");

        }else if((a*a)>(b*b)+(c*c)){
            System.out.println("TRIANGULO OBTUSANGULO");

        }else if((a*a)<(b*b)+(c*c)){
            System.out.println("TRIANGULO ACUTANGULO"); 

        }

        if(a >= b+c){
           System.out.println("NAO FORMA TRIANGULO");
        }else if( a == b && a == c){
            System.out.println("TRIANGULO EQUILATERO");

        }else if(a == b || b == c || c == a){
            System.out.println("TRIANGULO ISOSCELES");
        }else{
            System.out.println("");
        }


       }

    }

Answer 1

I think I found the solution, my idea was to sort the sides in a vector, since the library Arrays has the method sort(), it sorts the numbers of the vector in descending order.

For the vector to be ordered in ascending order just multiply the array by -1, follow the code:

Scanner sc = new Scanner(System.in);

double a,b,c,maior;

System.out.printf("Digite o valor de A: ");
a=sc.nextDouble();
System.out.printf("Digite o valor de B: ");
b=sc.nextDouble();
System.out.printf("Digite o valor de C: ");
c=sc.nextDouble();

//nomeia o vetor
//exemplo 1, 2, 3
double lados[] = {a,b,c};

//multiplica os valores por -1
//exemplo -1, -2, -3
for(int i=0;i<lados.length;i++) {
    lados[i]=-lados[i];            
}

//ordena os dados em ordem decrescente
//exemplo -3, -2, -1
Arrays.sort(lados); 

//multiplica os valores por -1 denovo
//exemplo 3, 2, 1
for(int i=0; i<3; i++){
    lados[i] =-lados[i];
}        
if(lados[0]>= lados[1]+lados[2]){
   System.out.println("NAO FORMA TRIANGULO");

}else if((lados[0]*lados[0]) == (lados[1]*lados[1])+(lados[2]*lados[2])){
    System.out.println("TRIANGULO RETANGULO");

}else if((lados[0]*lados[0])>(lados[1]*lados[1])+(lados[2]*lados[2])){
    System.out.println("TRIANGULO OBTUSANGULO");

}else if((lados[0]*lados[0])<(lados[1]*lados[1])+(lados[2]*lados[2])){
    System.out.println("TRIANGULO ACUTANGULO"); 

}

if(lados[0] >= lados[1]+lados[2]){

}else if( lados[0] == lados[1] && lados[0] == lados[2]){
    System.out.println("TRIANGULO EQUILATERO");

}else if(lados[0] == lados[1] || lados[1] == lados[2] || lados[2] == lados[0]){
    System.out.println("TRIANGULO ISOSCELES");
}else{
    System.out.println("");
}