Send GET parameters to a php using the exec command

Question

I am trying to send GET parameters to a php using the exec php command, but when I put the parameters the script does not run, it does not reach the other php, follows my code:

exec.php:

$cmd = 'php teste.php?id=10,11';
$pid = exec($cmd.' > /dev/null &');

php test.:

$ids = $_GET["id"];
echo $ids;

I don’t get error msgs.

Answer 1

From what I see, you are trying to pass an argument to the PHP script that runs on the command line.

On command line, not used $_GET to access arguments from a script. You must use the variable $argv to access these arguments.

Passing and accessing the arguments

Create a file cmd.php, do the following:

print_r($argv);

Run on command line:

>>> php cmd.php 1 2 3

The result will be:

Array
(
    [0] => cmd.php
    [1] => 1
    [2] => 2
    [3] => 3
)

Note that the first argument from $argv is the name of the running script. That’s always so.

If you want to get only the arguments after the script, you can use array_slice, thus:

print_r(array_slice($argv, 1))

When you run a script php via command line, each item separated by a space after php is considered an argument of the command.

I mean, you’re not gonna use the interrogation ? as you do in the case of browser query strings.

But what if I want to pass an argument that has space?

If you want to pass an argument that contains a literal space, you can use the quotes to delimit the argument.

Thus:

>>> php cmd.php "olá mundo"

Upshot:

Array
(
    [0] => cmd.php
    [1] => olá mundo
)

And if I want to quote as an argument?

Then you have to escape with the \.

Example:

>>> php cmd.php "olá \""

Upshot:

Array
(
    [0] => cmd.php
    [1] => olá "
)

And before you ask me "How to escape the bar too", I say just use another bar.

Example:

  >>> php cmd.php \\My\\Namespace

Exit:

Array
(
    [0] => cmd.php
    [1] => \My\Namespace
)

Count of past arguments

To count the number of arguments, you can also use the variable $argc.

Create a file count_args.php to test and place the following:

  print_r($argc)

Run on command line:

 >>> php count_args.php 1 2 3 4

The result will be:

5

Nothing prevents you from using count($argv) to tell the arguments.