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Good morning, you guys!
I would like to place the contents of a <td>
as a link so that the user can access the image that is in a folder on the server.
That’s the :
//Montando o corpo da tabela
$table .= '<tbody >';
while($r = mysqli_fetch_array($qry)){
$table .= '<tr>';
$table .= '<td>'.$r['ID'].'</td>';
$table .= '<td>'.$r['OQUE'].'</td>';
$table .= '<td>'.$r['NOME'].'</td>';
$table .= '<td>'.$r['IDENTIFIANT'].'</td>';
$table .= '<td>'.$r['PREDIO'].'</td>';
$table .= '<td>'.$r['POSTO'].'</td>';
$table .= '<td>'.$r['INICIO'].'</td>';
$table .= '<td>'.$r['DATA'].'</td>';
$table .= '<td>'.$r['MES'].'</td>';
$table .= '<td>'.$r['HORA'].'</td>';
$table .= '<td>'.$r['ANO'].'</td>';
$table .= '<td>'.$r['LOCALLESAO'].'</td>';
$table .= '<td>'.$r['TIPOLESAO'].'</td>';
$table .= '<td>'.$r['LADOLESAO'].'</td>';
$table .= '<td>'.$r['FONTELESAO'].'</td>';
$table .= '<td>'.$r['ACIDENTE'].'</td>';
$table .= '<td>'.$r['ATENDIMENTO'].'</td>';
$table .= '<td>'.$r['HOSPITAL'].'</td>';
$table .= '<td>'.$r['CONCEQUENCIA'].'</td>';
$table .= '<td>'.$r['FALHA'].'</td>';
$table .= '<td>'.$r['DESCRICAO'].'</td>';
$table .= '<td>'.$r['IMAGEM'].'</td>'; //É SÓ ESSA AQUI
$table .= '</form></td>';
If you can help me, I’d appreciate it. :)
It worked perfectly. I’ll just wait for the time stipulated by Stackoverflow to score as the right answer. Thank you!
– Mariana Bayonetta