How do not have a miss click on the next screen?

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I’m having a little problem with a quiz application. when the user clicks on the button the next question comes. put a delay of 1 sec. However, if the user clicks 2x on the button within this delay of 1 sec, when opening the next question it will already be clicked. 

     private void ResetTempo() {
     mCountDownTimer.cancel();
     mTimeLeft = StartTempo;
     try {
        new Thread().sleep(1000);
     } catch (InterruptedException e) {
        e.printStackTrace();
     }
     mCountDownTimer.start();
     }

           r4.setOnClickListener(new View.OnClickListener() {
          @Override
          public void onClick(View v) {
            r4.setEnabled(false);
            ResetTempo();         

            updatePerguntasoma(r.nextInt(mPerguntasomaLenght));
                    r4.setEnabled(true);
java android

  • Can you be more specific or show some example?

  • I have a quiz with one question and four answers, four buttons. If the user gives 2 clicks on the first answer... the first and second question are answered by the button. I showed you the code, 'cause I want a 1 sec Sleep.. Then the user of 2 clicks, the question waits 1 sec and is answer, opens the second question and is answered (after 1 sec too) also by double clicking on the first question. I can’t explain it any more clearly.

1 answer

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I believe that if you disable the button while in delay already solve.

myButton.setEnabled(false);

  • Good! I thought it was a good idea! It works, but the button is inactive! I made the button true again after the delay! but if I double click! the button is triggered, disabled, waited 1 second, goes to the next question, the button is enabled again, and(that click is "waiting" the button enable, and automatically the second question is already answered by the same button)

  • Then put a condition inside the click event to go to the next question only if the user answers the question.

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