While com Href - PHP

Question

Expensive;

I have this code:

<?php

    $sql = "select * from tabela where codsegur = '7562315'";

    $stm = $conexao->prepare($sql);
    $stm->execute();
    $count = $stm->rowCount();

    if ($count > 0) {
       while($row = $stm->fetch())  {
           echo "<a href=caminho/".$row['caminho']."></a>";
       }
    }
?>

The variable $row receives the SQL return above, and the array path would be the path where the file would be. In this case, wanted to concatenate the href along with the path and generate the file link on my download page. In short, when accessing the page and entering the code (7562315) in the form, present the file in question, whose file is with its path set in the array (path). To not need to put the whole form, I have put the direct code in SQL to give the return I need.

When I do this process, nothing happens, and it does not generate errors. When I give a echo in the $row['caminho'], appears the path that is set in the database.

Can someone assist me in what/where I am missing?

Note: Connection to database is Ok.

Grateful.

Answer 1

Your error is missing quotation marks for the parameter href. The right thing would be:

echo "<a href='caminho/".$row['caminho']."'></a>";

Leaving the content inside the parameter href in single quotes.