How to read a line in C

Question

How to read a row of integers and store in a dynamically sized array ?

Currently I read the line as string(although the input is only integers) using gets, only way it worked.

The code is like this:

    type def struct{char entradas[50];} Processo 

    int main(){[...] Processo processos; gets(processo[i].entradas); }

And it works, only I need it to be variable this size of inputs[]

Answer 1

You might as well continue with what you are doing and create a vector of a virtually unlimited size e.g entrada[500000];

Or create a buffer and load the items partially :

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

void* vetgen(void *vetor,int newsize,int size){
    void *newarr=malloc(newsize);
    memcpy(newarr, vetor,size);
    free(vetor);
    return newarr;
}
int main(){
    int* vetor,i,aux=1;
    vetor=malloc(sizeof(int)*256);
    do{
        scanf("%d ",vetor+i);
        i++;
        if(i%256==0){
            vetor = (int*) vetgen(vetor,i*(aux+1),i*aux);
            aux++;
        }
    }while(!feof(stdin));
}

This code above is just to give you an idea, to read C entries from stdin recommend using the fgets() e. g fgets (buffer, 256, stdin);