Script to check if directory is empty

Question

I’m knocking my head to create this script.

I need a script, can be in bash or php even, check if a directory has some file inside, that is not another directory.

This directory that I have to scan is in linux server that I have here in the company, so the script can be in bash, which I put to run daily on linux. Or in PHP, I make linux run the PHP file, without problems tb.

Someone knows how to do?

Answer 1

You can create alias.

Find empty directories (Shellscript):

 alias searchDirEmpty='dirEmpty() { find $1 -type d -empty -print; }; dirEmpty'

How to use: searchDirEmpty /path/to

Checks if a given directory is empty (Shellscript):

alias checkDirEmpty='checkDir() { [[ $(ls $1 | wc -l) == 0 ]] && echo "Diretório vázio"; }; checkDir'

How to use: checkDirEmpty /path/to

Answer 2

In php can be done so according to the Answer found in : https://stackoverflow.com/questions/7684881/php-how-to-list-files-in-a-directory-without-listing-subdirectories

$files = scandir($dir); 
foreach($files as $file){
    if(is_file($dir.$file)){
      ....

It uses scandir to recover all the contents of the folder($dir) and then uses is_file to check item by item if any of them is a file