0
I can’t create a filter through this query
that filters a bank search Mysql with PHP. I started editing it, but the problem is that I can’t generate this method using a variable that’s present on the screen. For example, I did it this way:
$result = $obj->getAll('usuarios_id IN (SELECT usuarios_id FROM usuarios WHERE empresas_id = 12');
In this case it works, and displays the results of empresa_id = 12
. I am trying to modify to pass a parameter instead of a fixed value (12). I tried so:
$result = $obj->getAll('usuarios_id IN (SELECT usuarios_id FROM usuarios WHERE empresas_id = ".$empresa."');
No results return to me. I’m having difficulty passing this parameter of $empresa
. The method was like this:
public function excelRelatorio() { $arrayRow = array('Nome','Forma Pagamento','Status', 'KM','Valor', 'Valor Extra', 'Data'); $this->geraExcelRelatorio($arrayRow); }
private function geraExcel($arrayRow,$empresa)
{
$this->load->helper('xls');
$arr[] = $arrayRow;
$obj = new Viagem();
$result = $obj->getAll('usuarios_id IN (SELECT usuarios_id FROM usuarios WHERE empresas_id = ".$empresa."');
if (isset($result) && count($result) > 0) {
foreach ($result['rows'] as $v) {
$arr[] = array(
utf8_decode($v->getUsuario()->getNome()), $v->getFormaPagamento()->getNome(), $v->getStatus()->getNome(), $v->getDistancia(), $v->getValor(), $v->getValorExtra(), dataHoraBr($v->getDataCriado()), $v->getEntregador()->getNome()
);
}
}
array_to_xls($arr, 'financeiro'.date("m-d-y").'.xls');
}
"usuarios_id IN (SELECT usuarios_id FROM usuarios WHERE empresas_id = '{$empresa}'"
try like this.– NoobSaibot
got thanks
– Mauricio3012