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I want to compare whether all elements of an array are between -4 and 4, if so, the algorithm will execute the method.
for(int i=0; i< j; i++){
if(vet[i] > -4 && vet[i] <4)
calcular(4);
}
1 answer
3
It is easier to reverse the condition and exit quickly if you have an element that does not fit in the filter, like this:
#include <stdio.h>
void filtro(int tamanho, int vet[]) {
for (int i = 0; i < tamanho; i++) if (vet[i] <= -4 || vet[i] >= 4) return;
printf("Está executando um método\n");
}
int main(void) {
int vet[] = { 1, 2, 3, 4 };
filtro(3, vet); //não considerará o último elemento que não encaixa no filtro
printf("Agora não vai passar pelo filtro");
filtro(4, vet);
}
See working on ideone. And in the repl it.. Also put on the Github for future reference.
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In what language? Do not use tags than you don’t want.
– Maniero
Anyone. I just want to see the logic.
– Wesley
What would be the doubt? It seems to me that the condition is correct.
– Sam
Got it now. You want to check all.
– Sam
That msm...................
– Wesley
It will be easier to limit the scope in just one language. Possible solutions for each language can vary greatly.
– Woss