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I am creating an application and need a way to upload xls/xlsx files by sending the file from the front end (Ajax) to the back end (Java) so it can be manipulated.
Ajax code:
$("#formulario").submit(function () {
var formData = new FormData(this);
$.ajax({
url: url,
type: 'POST',
data: formData,
success: function (data, status, jqxhr) {
alert('sucesso');
},
error: function(){
alert('deu erro');
},
cache: false,
contentType: false,
processData: false,
xhr: function() {
var myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) {
myXhr.upload.addEventListener('progress', function () {
alert('upando o arquivo');
}, false);
}
return myXhr;
}
});
});
Ajax Code is working perfectly, it runs and returns me the code 200. However I cannot 'receive' the file in Java.
Java code:
@POST
@Path("/upload")
@Consumes("multipart/form-data")
public Response create(@MultipartForm FileUploadForm input){
System.out.println("funcionou");
//manipulo o arquivo
return Response.ok;
}
I hope you can help me and guide me to make it work.
UPDATE
I made a change in ajax, and finally, I managed to get JAVA to receive the request
$(document).ready(function () {
$(function () {
var form;
$('#fileUpload').change(function (event) {
form = new FormData();
form.append('fileUpload', event.target.files[0]); // para apenas 1 arquivo
//var name = event.target.files[0].content.name; // para capturar o nome do arquivo com sua extenção
});
$('#btnEnviar').click(function () {
$.ajax({
url: 'http://localhost:8080/SferaCR/rest/importacao', // Url do lado server que vai receber o arquivo
data: form,
processData: false,
contentType: false,
type: 'POST',
success: function (data) {
alert('sucesso');
$('#fileUpload').val('');
},
error: function (){
alert('deu erro');
$('#fileUpload').val('');
}
});
});
});
});
However, the problem now is that in java, which is receiving the parameter 'input' as null. That is, the request will, from 'right', but the file is not sent.
where the variable is coming from
urlin your javascript code and what it contains within it?– CIRCLE
What JAX-RS implementation you’re using?
– Luídne
My suggestion is that you search the documentation of
FileUploadFormthat you are using. Most likely it is some library that works with Buffers... or bytearrays. In any of the options it is quite simple to convert to a file and save somewhere on your server.– Jorge Campos
@CIRCLE contains json (or xml), which returns the REST data.
– Erico Souza
@Luídne am not using any JAX-RS implementation. You recommend using it?
– Erico Souza
@Jorgecampos said thanks for your help. But even if this happened and I had some mistake there, would not have an Exception in java? Because nothing happens.
– Erico Souza
@Ericosouza what you mean is that you’re not printing the "worked". If so, that’s not what I had understood. If this is the case, what is being passed in the parameter
urlof the ajax function?– Jorge Campos
@Jorgefields is not that it is not printing did not work. The problem is that my ajax, sends upload file. But java 'does not receive'. Something like that.
– Erico Souza
How is your form tag in your html/jsp, the form with id 'form'?
– Jorge Campos
@Jorgecampos follows below:

<form id="formulario" method="post" name="fileupload" enctype="multipart/form-data" method="post">
 <input name="arquivo" type="file" />
 <button>Enviar</button>
</form>– Erico Souza
The url, I’m using a Rest (json/xml), which I used in other templates with Formularios and ok. But for uploading files, I can use the same?
– Erico Souza
Did you find a solution? Poste as an answer to help other people.
– Maniero
@Ericosouza found some solution?
– Wellington Avelino