0
I looked at some sites and saw some things about it, but I’m not getting the logic behind the page on demand.
jQuery(document).ready(function(){
jQuery('#btnpaginas').click(function(){
var dados = jQuery( this ).serialize();
jQuery.ajax({
type: "POST",
url: "paginacao.php",
data: dados,
success: function(data)
{
$(".paginacao").html(data);
}
});
return false;
});
});
<button id="btnpaginas">Carregar mais</button>
PHP
$inicio = 5;
$stmt = $conecta->prepare("select * from postagem order by idpost desc limit $inicio " );
$stmt->execute();
I know I’m doing it wrong. It already starts with 1 record and when I press the "press more" button it shows the first record, which already had, and four more. Only with this code that I made, it will not load 5 more if I click again, I want to know how to do for whenever I click the button, it show 5 more records to my posting system.
Lendro, the idea is that when you click on the "press more" button automatically appear 5 more posts below the existing ones. It’s a site where there will be a lot of people doing a lot of posts, like facebook, but without automatic scrolling. From what I saw this code that you put will only show up to 5 posts at most. The idea is not to use select in this case. Have some other idea?
– Luizinho
Sorry, after your comment I realized that I misunderstood your question. I edited the answer, but it won’t do much good. When the person clicks on the button, a request will be made for your file. php, in the file will be made a query and you will return the result of this query pro your html file, and you have to handle the result of the query within the function
success(), very likely to be received aarrayand the ideal is to treat it with aforeach.– Leandro Lima