What is the logic for calculating the percentage of victory, draw and defeat?

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I’m wondering the logic of how to calculate the percentage of tables in a football game.

Tabela da porcentagem dos jogos.

For example, I put a quick Excel tabelinha here just for demonstration. In red is the real percentage, and next is the percentage that I got.

So my question is how to reach 100% when you win all, 77% when you win 2 and draw 1 and when it’s 44% when you win 1, draw 1 and lose 1.

What is the logic used in this calculation? I tried to break my head but at this point, I did not get any results.

  • 1

    You want in PHP or in Excel? You have to decide, if not you keep enlarging the question.

  • 1

    Where did these numbers come from? Who said this is the real percentage? Because these percentages of 77 and 44 don’t make sense. The correct would be 66 and 33.

  • If the problem is only of mathematics, it is not in the scope. If it is of programming, click on [Edit] and put only one [mcve] of the problem in the post.

  • Bacco, colleague. This question has been answered for a long time. This question was supposed to be closed. I don’t know why it’s pending if I’ve already marked the answer.

2 answers

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To calculate the percentage in this case, with 3 elements, you calculate the difference of the item you are looking for in relation to the total sum. Ex:

  • 3 victories
  • 4 defeats
  • 1 draw

To know the % of victories:

3 / (3 + 4 + 1)
3 / 8
0,375
37,5% de vitórias

To know the % of defeats:

4 / (3 + 4 + 1)
4 / 8
0,5
50% de derrotas

To know the % of draws:

1 / (3 + 4 + 1) * 100
1 / 8
0,125
12,5% de derrotas

Soon:

37,5% + 50% + 12,5% = 100%
  • Ah! I understood Diego. I was trying to calculate in this logic that you showed there. But I was doing it wrong. That was my logic, just the execution that was wrong. Thank you.

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Probably doesn’t matter to the colleague anymore, but I’ll answer in case someone searches:

If you are considering the score of football games currently, that is, 3 points for a win, 1 point for a draw and 0 points for defeats, then we do the following:

We calculated the maximum number of points a team could earn: For example, if she played 8 matches, she can earn a maximum of 24 points =(8*3).

So we have number 24.

Now, suppose that this team in these 8 matches won 5, drew 1 and lost 2. In this case (according to the rules of football) she added 16 points.

Now just divide 16 by 24 and multiply by 100 to get the percentage

=(16/24)*100= 66,66

That is, this team had a 66,66% in the 8 matches that played.

Now an observation, if you want to do this calculation using a general basis, without using the scoring system of football or another sport, you can put a win as being 100%, a 50% draw and a 0% defeat. If we use this system in the example above, for example, we would have =8*100%= 800% (which is the maximum number we could reach), as the team won 5 matches and drew 2, he would have 550%, then just split =550%/800% that would give 68.75%.

Although the result is different, both calculations are correct as they use different bases.

  • In fact the answer has already been answered. And I already got what I wanted. The colleague Diego already helped me. It was for this question is closed. I don’t know why it’s open yet.

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