-4
For example from 0 to 60. Obviously I know how many numbers there are, but what I know is how to make my algorithm figure that out mathematically.
1 answer
7
function quantosNumerosExistem(x, y) {
return Math.abs(y - x) + 1;
}
document.write(
" De 3 até 10: " + quantosNumerosExistem(3, 10) + "<br>" +
" De 0 até 60: " + quantosNumerosExistem(0, 60) + "<br>" +
" De -2 até 2: " + quantosNumerosExistem(-2, 2) + "<br>" +
" De 0 até 0: " + quantosNumerosExistem(0, 0) + "<br>" +
" De 0 até 1: " + quantosNumerosExistem(0, 1) + "<br>" +
" De -10 até -8: " + quantosNumerosExistem(-10, -8)
);
-
1
Boot in
Math.absbeforexandyin case ofx = -90; y = -12;otherwise will go wrong,Math.abs(x) -
1
@Guilhermelautert Feito.
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numero maior - numero menor = total de numeros entre eles– user28595
Make a
fortotaling/counting the iterations. In positive numbers it is very evident that the last is total number but in negative numbers ... for example how many numbers you have of-3until0?– rray
@rray I find a very tie Overkill to the problem.
– Oralista de Sistemas
Hello David. You can clarify the question and include an example where you cannot write code to solve, and also the programming language you use.
– Sergio
Overkill is an American thrash metal band formed in 1980 in New Jersey and in Renam’s commentary which means?
– user60252
@Leocaracciolo too much work/effort for little result in other words the cost is too high. Then you run out of coffee and give that kind of suggestion haha xD ... Epic fail...
– rray
@rray in qq right case of a simple mathematical operation is a lot of work/effort
– user60252
@Leocaracciolo yes, if you want to take the doubt can make a measurement.
– rray
@rray is not the case, the customer is rich and willing to pay qq price since he had in his hands something very cheap and fundamental. In fact the question does not speak of performance.
– user60252