Dictionary file

Question

I am trying to turn a file into dictionary but is giving the following error:

Traceback (Most recent call last): File "C: Users taynan Appdata Local Programs Python Python36-32 Project CRUD Interface.py", line 46, in consultarProfessor(cpfP, arqProfessores) File "C: Users taynan Appdata Local Programs Python Python36-32 Project CRUD Modulodefuncoes.py", line 38, in consultarProfessor key, val = line[:-1]. split() Valueerror: not enough values to unpack (expected 2, got 0)

Can anyone identify where the bug is? Because I don’t know :/

Filing cabinet:

{'Nome': 'd', 'Cpf': '33', 'Departamento': 'a'}
{'Nome': 'f', 'Cpf': '22', 'Departamento': 'g'}
{'Nome': 'a', 'Cpf': '13', 'Departamento': 'b'}
{'Nome': 'x', 'Cpf': '24', 'Departamento': 'd'}

Here is a part of the code, because it is very large:

def consultarProfessor(cpf, arquivoEspecifico):
arquivo = lerArquivo(arquivoEspecifico)
for linha in arquivo:
    linha = linha.replace('"',"")
    chave, valor = linha[:-1].split()
    dicProfessores[chave] = valor
if cpf in dicProfessores.values():
    dicProfessor = dicProfessores[cpf]
    arquivo.close()                                            #definindo uma variavel para a chave do dicionario de professores
    print(dicProfessores)
else:
    print("Este professor não é funcionário desta faculdade.")

obs. I’ve tried using dicProfessores = eval(linha[-1]), but it was making a lot of mistakes.

#Edit: Consegui criar o dicionário, mas ele está saindo todo errado:
def file_to_dict(arquivoEspecifico):
dic = {}
arquivo = lerArquivo(arquivoEspecifico)
for linha in arquivo:
    linha = linha.replace('"',"")
    valor = linha[:-1].split()
    chave = linha[:-1].split()
    for v in valor:
        v = v.replace(",","")
        v = v.replace("{","")
        v = v.replace("}","")
        v = v.replace(":","")
        v = v.replace("'","")
        for c in chave:
            c = c.replace(",","")
            c = c.replace("{","")
            c = c.replace("}","")
            c = c.replace(":","")
            c = c.replace("'","")
            dic[c] = v
print(dic)
return dic

Here’s how it’s coming out:

{'Nome': 'g', 'd': 'a', 'Cpf': 'g', '33': 'a', 'Departamento': 'g', 'a': 'a', 'f': 'g', '22': 'g', 'g': 'g'}

Answer 1

The module json can facilitate the construction of its function. The function loads() turns str into Dict with the need to follow only a few pre-established rules. In your case, the only things you will have to deal with are the simple quotes and line breaks. But these questions can be corrected with the .replace() that you are already using.

Since your code is not indented, I don’t understand if your intention is to make a dictionary with all the data, and only then do the query, or if you want to do the query line by line.

If you are just doing the query line by line, you can do so:

import json

def consultarProfessor(cpf, arquivoEspecifico):
    with open(arquivoEspecifico, "r") as arquivo:
        for li in arquivo:
            li = li.replace("'", "\"")
            li = li.replace("/n", "")
            li = json.loads(li)   # <-- Transforma str em dict
            if str(cpf) == li["Cpf"]:
                return li
        return "Não encontrado"

file = "lista.txt"
cpf_consult = 24

print(consultarProfessor(cpf_consult, file))

Answer 2

Buddy, your mistake is on the line

chave, valor = linha[:-1].split()

such allocation is not permitted for that particular case Well I tested the assignments separately and it worked out that way

chave = linha[:-1].split()
valor = linha[:-1].split()

as shown at the prompt

However, that alone does not solve your problem... that said I made this implementation functional

# Esse código serve se seguir esse modelo  
# Esse modelo foi usado como exemplo -> suponha que linha = "{'Nome': 'd', 'Cpf': '33', 'Departamento': 'a'}" 
dict = {}
for linha in arquivo:
    linha = linha.replace("'", "")

    b = linha.split(',')

    for i in b:
        c  = i.split(':')
        c[0] = c[0].replace("{","")
        c[0] = c[0].replace("}","")
        c[0] = c[0].replace(":","")
        c[1] = c[1].replace("{","")
        c[1] = c[1].replace("}","")
        c[1] = c[1].replace(":","")
        dict[c[0]] = c[1]
print dict

The code results in a dictionary with keys and values: