Check if URL is different in PHP

Question

In Javascript, we can check if the url is different, we have window.location.href

You can do it:

var urlAtual = window.location.href;
var urlCadastro = "www.teste.com/cadastro";
if(urlAtual != urlCadastro){
  window.location.href = "www.teste.com/login";
}

What I tried would work?

$atacadoLogado = $this->helper('customer')->isLoggedIn();
$urlDoCadastro = "https://www.meusite.com/cadastro";
$pegarDominio = $_SERVER['HTTP_HOST'];
$urlAtualizada = (isset($_SERVER['HTTPS']) ? "https" : "http") . "://" . $pegarDominio . $_SERVER['REQUEST_URI'];
if(!$atacadoLogado && $urlAtualizada != $urlCadastro){
    header("Location: https://www.meusite.com/login");
}

Answer 1

You can use the super global $_SERVER

$server = $_SERVER['SERVER_NAME'];
$endereco = $_SERVER ['REQUEST_URI'];

 $clienteLogado = $this->helper('customer')->isLoggedIn();
$urlCadastro = $server.$endereco
if(!$atacadoLogado && !$urlCadastro){
    header("Location: http://www.meusite.com/login");
}

At this link you find all the indexes and function of each on this super variable $_SERVER.

Answer 2

Yes friend is possible let’s take an example

$url = "https://www.google.com";
//Aqui ira pegar o dominio
$dominio= $_SERVER['HTTP_HOST'];
//Aqui ira concatenar com o http:// ou https:// e salvar em url

 $urlAtual = (isset($_SERVER['HTTPS']) ? "https" : "http")."://".$dominio. $_SERVER['REQUEST_URI'];
//Verifica se é diferente
if($url != $urlAtual){

echo "Diferente";
}
else{
echo "Não diferente";
}