Vector error(one-dimensional matrix)

Question

Can anyone tell me what’s wrong with this algorithm?

Make a program where the user enters with N values and stores the first 10 even numbers in a vector called even. When you reach the tenth even number, close the program and print the vector....

#include<stdio.h>
#include<stdlib.h>
#include<locale.h>

int par[10],a,count;

main(){
    setlocale(LC_ALL, "Portuguese");
    while(count<10){
            printf("Digite um número: \n");
            scanf("%d",&a);
            if(a%2==0){
                par[a]=a;
                a++;
                count++;
            }//fim do if

    }//fim do while
    for(a=1;a<=10;a++){
        printf("valores de vetor: %d \n",par[a]);
    }//fim do for



    system("pause");
}//fim do main

What’s happening is the following, at the time of printing the even numbers of the first vector up to the ninth, it’s okay, but the printing of the tenth vector, is adding "1" to the number, for example if I type the following sequences, 2 4 6 8 10 2 4 6 8 10 it will print: 2 4 6 8 10 2 4 6 8 "11"...

Answer 1

C++ arrays start at 0. I believe the error is in the final loop, where you are iterating the array outside the desired range.

Change your final loop to

for(a=0;a<10;a++){
    printf("valores de vetor: %d \n",par[a]);
}//fim do for

Also, use the variable count instead of a to fill the array. ( and remove the a++ unnecessary )

while(count<10){
   printf("Digite um número: \n");
   scanf("%d",&a);
   if(a%2==0){
     par[count]=a;
      count++;
   }//fim do if
}

Follows algorithm working as desired: http://ideone.com/7LOOBg