Notice : Array to String Conversion in

Question

I have a problem with the following code :

<select name="tipoPessoa" class="form-control">
    <?php 
        $tipos = array("Pessoa Fisica","Pessoa Juridica");
        $tipoSemEspaco = str_replace(" ","",$tipos);

        foreach ($tipos as $tipo):
        $esseEhOTipo = get_class($pessoa) == $tipoSemEspaco;
        $selecaoTipo = $esseEhOTipo ? "selected='selected'" : "";
    ?>
  // Linha 22 <option value="<?=$tipoSemEspaco?>" <?=$selecaoTipo?>>
                <?=$tipo?>
            </option>       

    <?php  endforeach ?>

</select>

When I open the browser console, it informs me a Notice:

Array To String Conversion in line 22

I am trying to assign the value of the field without the spaces and this giving this error.

Answer 1

The reason for the mistake is because $tipoSemEspaco is a new array, which is independent of the $tipos.

An easy fix:

Add the index in the foreach:

foreach($tipos as $index => $tipo){ 
    /...
}

Then use it to get the respective $tipoSemEspaco:

<?=$tipoSemEspaco[$index]?>

In the end:

<select name="tipoPessoa" class="form-control">
    <?php 
        $tipos = array("Pessoa Fisica","Pessoa Juridica");
        $tipoSemEspaco = str_replace(" ","",$tipos);

        foreach ($tipos as $index => $tipo):
        $esseEhOTipo = get_class($pessoa) == $tipoSemEspaco;
        $selecaoTipo = $esseEhOTipo ? "selected='selected'" : "";
    ?>
  // Linha 22 <option value="<?=$tipoSemEspaco[$index]?>" <?=$selecaoTipo?>>
                <?=$tipo?>
            </option>       

    <?php  endforeach ?>

</select>

---

Another option would be to add something like:

$tiposPessoasDisponiveis = [
   0 => ['TextoHumano' => 'Pessoa Fisica', 'ValorMaquina' => 'PessoaFisica'],
   1 => ['TextoHumano' => 'Pessoa Juridica', 'ValorMaquina' => 'PessoaJuridica'],
];

Since there are few options and it does not tend to change this often, IN THIS CASE, this could be feasible, then:

<select name="tipoPessoa" class="form-control">
        <?php 

            $tipos = [
                0 => ['TextoHumano' => 'Pessoa Fisica', 'ValorMaquina' => 'PessoaFisica'],
                1 => ['TextoHumano' => 'Pessoa Juridica', 'ValorMaquina' => 'PessoaJuridica'],
            ];

            foreach ($tipos as $tipo):
                $esseEhOTipo = get_class($pessoa) == $tipo['ValorMaquina'];
                $selecaoTipo = $esseEhOTipo ? "selected='selected'" : "";
                ?>
                <option value="<?=$tipo['ValorMaquina']?>" <?=$selecaoTipo?>>
                    <?=$tipo['TextoHumano']?>
                </option>

            <?php  endforeach ?>

</select>

---

Personally I don’t think it’s very good, because it simply makes it confusing to understand what each thing is, are two different arrays and that has a direct relationship, that is my opinion, precisely for this I would prefer to do:

<select name="tipoPessoa" class="form-control">
        <?php 

            $tiposPessoasDisponiveis = ['Pessoa Fisica', 'Pessoa Juridica'];

            foreach ($tiposPessoasDisponiveis as $tipoPessoa){

                $tipoSemEspacamento = str_replace(' ', '', $tipoPessoa);

                $estaSelecionado = get_class($pessoa) == $tipoSemEspacamento;

                $atributoOptionHTML = '';
                $atributoOptionHTML .= 'value = "'.$tipoSemEspacamento.'"';
                $atributoOptionHTML .= $estaSelecionado ? 'selected' : '';

                ?>
                <option <?= $atributoOptionHTML ?>>
                    <?= $tipoPessoa ?>
                </option>

            <?php  } ?>

</select>

Finally, add the str_replace within the foreach, in this way it becomes clear what is the purpose of it, I renamed the functions so that try to present better their "functions", in my view. But logically this is totally optional.

Answer 2

Yes, in fact you are trying to assign an array as value, where it should be string. This is because in this expression:

$tipos = array("Pessoa Fisica","Pessoa Juridica");
$tipoSemEspaco = str_replace(" ","",$tipos);

You are trying to replace part of the array $tipos. The function that I thought most appropriate for your operation is the implode. It would be something like:

$tipos = array("Pessoa Fisica","Pessoa Juridica");
$tipoSemEspaco = implode(" ",$tipos);

And so you would actually have a string in the variable $tipoSemEspaco

Answer 3

You are assigning an array type parameter to a function that should receive the string type.

A suggestion for correction:

<select name="tipoPessoa" class="form-control">
    <?php 
        $tipos = array("Pessoa Fisica","Pessoa Juridica");

        foreach ($tipos as $tipo):
        $tipoSemEspaco = str_replace(' ', '', $tipo);
        $esseEhOTipo = get_class($pessoa) == $tipoSemEspaco;
        $selecaoTipo = $esseEhOTipo ? "selected='selected'" : "";
    ?>
    <option value="<?=$tipoSemEspaco?>" <?=$selecaoTipo?>>
                <?=$tipo?>
            </option>       

    <?php  endforeach ?>

</select>

In this correction I chose to be less invasive as possible, keeping its original code.

_{*I abstain from commenting on other issues.
The above code should solve the main problem.}