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Galera is the following trying to encode a message with RSA, and for that precise convert the characters to decimals and group them in 3 in an array to then do the calculations. But I am going through the following problem after pre-encoding the characters to the ASCII decimals and tries to group them into groups of 3 the uppercase characters if composed by only 2 digits they are only in 2 digits. Follow the code below:
<?php
$string = 'ThomSon';
$valS = strlen($string);
$code = '';
$aCode = [];
$valC = 0;
$pi = 0;
$pf = $valS - 1;
for ($i = 1; $i <= $valS; $i ++) {
array_push($aCode, ord(substr($string, $pi, -$pf)));
$pi ++;
$pf --;
}
$code = implode('', $aCode);
$valC = strlen($code);
$pi = 0;
$pf = $valC - 3;
$loop = true;
for ($i = 1; $loop != false; $i ++) {
if (implode('', $aCode) == $code) {
$loop = false;
} else {
$frag = substr($code, $pi, -$pf);
array_push($aCode, $frag);
$pi += 3;
$pf -= 3;
}
}
echo $string . '<br>';
echo $code . "<br>";
for ($i = 0; $i < count($aCode); $i ++) {
echo "<br>M($i) = {" . $aCode[$i] . "}";
}
Does anyone know what it might be ?
related (for reference): http://answall.com/questions/168087/loop-infinito-ao-gerar-a-chave-publica-do-rsa
– Daniel Omine
Could not use openssl? See for help: http://stackoverflow.com/questions/31922094/php-rsa-key-creation
– Daniel Omine
I’m doing this to study the same algorithm.
– ayelsew