Flashing image in Chrome

Question

I upload a PHP file that brings me an image in jpg. Code:

<?php
$url = "http://site.com.br/sistema/";
?>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

<script type="text/javascript">
var auto_refresh = setInterval(
function ()
{
$('#load_tweets').load('arquivo.php').fadeIn("slow");
}, 1000); // refresh every 10000 milliseconds
</script>

<div id="load_tweets">
</div>

php file is like this:

<?php
$conecta = mysql_connect('localhost','teste','teste')or die(mysql_error());
$banco = mysql_select_db('nomeBanco');

$selecionaTabela = mysql_query("SELECT * FROM noticias WHERE id = '187'")or die(mysql_error());
$dados = mysql_fetch_array($selecionaTabela);
?>

<img src="modulos/upload/<?php echo $dados['fotoEvento'];?>" alt=""/>

But in Chrome the image keeps flashing, already in Mozilla no!

Answer 1

Be that as it may, do not replace all the contents of the div #load_tweets once a second. Only search for new content, and enter at the end of the div if there is.

I do not know exactly what the purpose of its application, but the most common is exactly what bfavaretto spoke: display only new content. For this:

1) Where a new content is inserted in the hardcore bank a insertion date.

2) Each access to the ".php file" record the date/time of access in the user’s session.

The information 1 and 2 will allow you to know when the content was entered and which was the last time the user uploaded the content. Just consult only content whose insertion date is longer than the date the user last loaded the contents.

Ex:

$ultimaVisita = empty($_SESSION['ultimaVisita'])?'0000-00-00 00:00:00':$_SESSION['ultimaVisita'];


$selecionaTabela = mysql_query("SELECT * FROM noticias WHERE id = '187' AND data_insersao > '".$ultimaVisita."'")or die(mysql_error());
$dados = mysql_fetch_array($selecionaTabela);

$_SESSION['ultimaVisita'] = Date('Y-m-d H:i:s');