Error checking IF with array in PHP

Question

I’m trying to make a if within a foreach and the situation is as follows:

I have a array who I called $plates who returns like this:

array(2) { [0]=> array(1) { ["chave"]=> string(1) "1" } [1]=> array(1) { ["chave"]=> string(1) "3" } }

And I tried this code:

foreach($matriculas as $matricula){
        if(in_array($row['id_curso'],$matricula)){
            echo '<a href="" class="btn btn-success disabled">Matriculado</a>';
        }else{
            echo 'nois';
        }
    }

I would like to show the information if the value of $row['id_curso'] exist in $matricula, if it does not exist it should show any button. The problem is that it displays both, ie existing $row['id_curso'] in $matriculas or not existing. There is a way to correct this?

Answer 1

The problem is in logic. You are "printing" the two results by the fact of your array be multidimensional, then for each array intern he tests the if/else even though the value has already been found in the first iteration, it will do the test until the arrays interns.

Here’s a possible solution:

$matriculas = array(array('chave'=>1), array('chave'=>3));
$row['id_curso'] = 3;
$saida = false;

foreach($matriculas as $matricula){
    if(!$saida)
        $saida = (in_array($row['id_curso'],$matricula));
}
echo ($saida == 1) ? '<a href="" class="btn btn-success disabled">Matriculado</a>' : 'qualquer coisa';

I used an auxiliary variable called $saida to control. It starts with false. So for every turn of the foreach I test to see if "found" something, because if she gets true(found the element) is because you no longer need to take the test.

Answer 2

That would work too!

$matriculas = array(array('chave'=>1), array('chave'=>3));

    foreach($matriculas as $obj){
        foreach ($obj as $value){
            if($value == $row['id_curso']){
                echo '<a href="" class="btn btn-success disabled">Matriculado</a>';
            }
            elseif ($value =! $row['id_curso']){
                echo 'nois';
            }
            }
        }

Answer 3

What happens is, for each item in the list it checks, then it will see there, the array has 1, 3, 5, 7. it takes element id 5

He’ll be talking, no, no, yes, no. What you need to do is find the element in there with the loop, and exit the loop with the information whether you found it or not, then take action.

foreach($chaves as $arrayChaves){
    if(in_array($row['chave'],$arrayChaves, false)){
        achou = true;
        break;
    }
}
if($achou) {
    echo '<a href="" class="btn btn-success disabled">Matriculado</a>';
}else{
    echo 'nois';
}

So it worked perfectly, but thanks to everyone who tried to help.

Answer 4

I tested the following code and worked correctly:

<?php
$matriculas = array(array('chave'=>1), array('chave'=>3));

foreach($matriculas as $matricula){
        if(in_array(1,$matricula)){
            echo 'Encontrado';
        }else{
            echo 'Não Encontrado';
        }
    }
?>

In your case:

<?php
$matriculas = array(array('chave'=>1), array('chave'=>3));

foreach($matriculas as $matricula){
        if(in_array($row['id_curso'],$matricula)){
            echo 'Encontrado';
        }else{
            echo 'Não Encontrado';
        }
    }
?>

If not, check the value of $row['id_curso'] if that’s correct.

The content of $matriculas has to be a array ? For there may be other ways to do what you need.