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I have a form that lists several records and I want to update the status field of these records but at once but I am not able to.
my for and code:
<form id="form1" name="form1" method="post" action="">
<?php while($row_table = mysqli_fetch_array($table)) { ?>
<td height="30"><input name="id[]" type="hidden" id="id[]" value="<?php echo $row_table['id'];?>" /></td>
<td height="30"><?php echo $row_table['col1'];?></td>
<td height="30"><?php echo $row_table['col2'];?></td>
<td height="30"><?php echo $row_table['col3'];?></td>
<select name="status[]" id="status[]">
<option value="0"<?php if($row_table['status']==0) echo 'selected="selected"';?>>Novo</option>
<option value="1"<?php if($row_parceiro['status']==1) echo 'selected="selected"';?>>Ativo</option>
<option value="2"<?php if($row_parceiro['status']==2) echo 'selected="selected"';?>>Inativo</option>
<option value="3"<?php if($row_parceiro['status']==3) echo 'selected="selected"';?>>Rejeitado</option>
</select>
<input type="submit" name="atualizar" id="atualizar" value="Atualizar" />
<?php } ?>
</form>
<?php
if(isset($_POST)){
$count = count($_POST['id']);
$i = 0;
while ($i < $count) {
$id = $_POST['id'][$i];
$status = $_POST['status'][$i];
$query = mysqli_query($con,"update table set status = '$status' where id = '$id'");
echo '<META HTTP-EQUIV="Refresh" Content="0; URL=index.php">';
++$i;
}
}
?>
hi @Ivan, tested and is not updating...
– user26858
What problem is occurring?
– Ivan Ferrer