reset problem in C code

Question

I would like help with the code I’m having a problem that follows in the image:

I’m using this code:

#include <stdio.h>
#include <stdlib.h>

int main ()
{
    float CP, LP, PP, LA, AA, AT, AAZ, PL, PC, FP;
    int QA;
    printf ("\nDigite os dados da picina");
    printf ("\nComprimento, Largura, Profundidade: \n");
    {
        scanf("%f,%f, %f", &CP, &LA, &AA);
        PL = 2*CP*PP;
        PC = 2*LP*PP;
        FP = CP*LP;
        AT = PL+PC+FP;
        AAZ = LA*AA;
        QA = ((AT/AAZ)*1.05);
    }
    printf("\nA quantidade de azulejos para o revestimento da piscina e: %f", QA);
    system("PAUSE");
}

Answer 1

Mete

    if (scanf("%f%f%f", &CP, &LA, &AA) != 3) /* erro */;

Instead of

    scanf("%f,%f, %f", &CP, &LA, &AA);

---

The conversion "%f, %f, %f" means to read an optional float preceded by spaces, a comma, another float (with optional space before), another comma, optional space, and another float with optional space.

With the input "10" the variables LA and AA are not allocated and the programme makes wrong accounts.

---

Even better and input with fgets() and then sscanf() to assign value to variables

printf("Valores? ");
if (!fgets(tmp, sizeof tmp, stdin)) /* error */;
if (sscanf(tmp, "%f%f%f", &CP, &LA, &AA) != 3) /* error */;

Answer 2

In addition to the problem presented by @pmg, you are also not initiating variables PP and LP, which caused the program to run at unknown values for these variables. Ironically, these values must have been extremely low when you ran your code (values like 5.88639522e-039 and 1.12103877e-044), which in practical terms is zero.

Similarly, as the variables were not initialized, such values could have been extremely high, and consequently the result would be another.

With this (recital PP and LP null), PL, PC and FP were also zeroed because they multiply values PP and LP.

PL = 2*CP*PP;
PC = 2*LP*PP;
FP = CP*LP;

And with that, AT will also be zero.

AT = PL+PC+FP;

And finally, QA also.

QA = ((AT/AAZ)*1.05);

With this, independent of the input value, the result will be zero (because QA is zero):

printf("\nA quantidade de azulejos para o revestimento da piscina e: %f", QA);