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I have an Ajax script here that his function is as follows.. I have a news system, which by clicking on the title will open a modal and show me the news data (title, text, author).. but I don’t know what to put in PHP..
This is the js code
var News = {
Init: function(id) {
$.ajax({
url: 'noticia.php',
type: 'POST',
dataType: 'json',
data: {'id': id},
beforeSend: function(){
$('body').animate({'opacity':'0.5'});
},success: function(data) {
$('body').animate({'opacity':'1'});
var Html = '';
Html+='<div id="modal" class="animated bounceInDown">';
Html+=' <div class="ler_content animated bounceInDown"> <div id="close_new" onclick="Alerta.Close()"></div>';
Html+=' <div class="titulo">';
Html+=' <div class="img" style="background: url('+data['imagem']+');">';
Html+=' </div>';
Html+=' <div class="autor">'+data['autor']+'</div>';
Html+=' <span>'+data['titulo']+'</span>';
Html+=' </div>';
Html+=' <div class="texto">'+data['texto']+'</div>';
Html+=' </div>';
Html+=' </div>';
$('body').prepend(Html);
}
})
}}
what I’m trying to put in the news.php is this, but I know it’s wrong..
$id = mysql_real_escape_string( $_GET['id'] );
$data = array();
$sql = "SELECT id, titulo, imagem, autor, texto
FROM noticias
WHERE id=$id
ORDER BY id";
$res = mysql_query( $sql );
while ( $row = mysql_fetch_assoc( $res ) ) {
$data[] = array(
'id' => $row['id'],
'titulo' => $row['titulo'],
'imagem' => $row['imagem'],
'autor' => $row['autor'],
'texto' => $row['texto'],
);}
echo( json_encode( $data ) );
Help me!!
Where’s the problem? Some error or something that doesn’t work?
– Sergio
when I open the news she doesn’t show what she should
– Nicholas Ruschel Krüger
Some mistake? shows something? what gives
console.log(data);
within thatsuccess
ajax?– Sergio
beforeSend: Function(){ $('body'). Animate({'opacity':'0.5'}); },Success: Function(data) { $('body'). Animate({'opacity':'1'}); If it does not return the "sucess" page it is 0.5 of transparence..
– Nicholas Ruschel Krüger
You know what it is
console.log
? you already tested that I asked?– Sergio
I don’t understand much of it, in the same already in another function has a "console.log('Init');"
– Nicholas Ruschel Krüger
Read this http://answall.com/q/38057/129 and then answer the question here in the comments.
– Sergio
Man, I don’t quite get it, but it sums me up, whatever I do?
– Nicholas Ruschel Krüger
The best way to help you is to get you to read that question and answers. I’ve asked you what I need to know to help you. I’m waiting for the answer if you want more help. Believe me it’s worth reading :)
– Sergio
Sergio, I don’t understand this language, I read what you told me and I got lost in the subject..
– Nicholas Ruschel Krüger
https://www.youtube.com/watch?v=eSPMRDcq9Co
– Sergio
ok, I think I understand now, I added to the end of the function News console.log('News'); and I checked that the sucess modified my body by adding a style="opacity: 0.5;", but it did not show the rest that it should
– Nicholas Ruschel Krüger
It executes "beforeSend: Function(){ $('body'). Animate({'opacity':'0.5'}); }" but does not display the successor afterwards
– Nicholas Ruschel Krüger
Sergio, now yes it is working, but a detail, the values are returning as "Undefinied"
– Nicholas Ruschel Krüger