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I’m needing to reverse an A stack using another additional stack B and some variables in pseudo code. For the stack A to be reversed at the end of the algorithm. Someone can help?
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I’m needing to reverse an A stack using another additional stack B and some variables in pseudo code. For the stack A to be reversed at the end of the algorithm. Someone can help?
1
When stacking, the last entry becomes the first exit. Knowing this, just remove the stack elements at the same time you add it in another.
Cell A = 5, 4, 3, 2, 1 (Top)
Stack B;
Cell A = 5, 4, 3, 2 (Top)
Cell B = 1;
Cell A = 5, 4, 3 (Top)
Cell B = 1, 2;
etc..
R.Carvalho, I need to invert to A to B, but I need to invert to A so that it is reversed from A initially. That is, I need the stack A to be reversed using the B and some variables so that when it goes back to A it is totally reversed
At the end of this example, Voce will have the stack B reversed to A, now it is necessary to pass B to A using variables, to the point that A is exactly like B now, reversed.
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Is battery B obligatory? Using Bubble Sort nor is it necessary to have another battery.
– user28595
Yes Diego, it is mandatory to use a stack B and after reversing on stack B, use variables to return the elements to stack A.
– Carlos Diego