Incremental result?

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I have a doubt about this expression:

y-=++x

I can divide this expression in two?

x= x+1 

and then?

2 answers

4


I don’t know if this is what you’re looking for.

As you’ve already shown one who is

x = x+1;

below this equation just put this one that will work normally

y-=x; or y = y- x;

2

In fact, although it works, it is hardly readable in this way and can mislead the interpretation. It would be better so:

x++;
y -= x;

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