Grab a plugin selector

Question

I’m trying to create a plugin but I can’t catch the selector, and it was even removed from version 1.9.

If I use $(this).selector in the plugin, it returns a string #div #elementoA, #div #elementoB. I’ve tried to use this.each to try to pick up individually, but I couldn’t.

I need a way that returns either an array, or an object, but with the individual selectors: '[#div #elementoA] [#div #elementoB]. It is possible using 1.9?

$('#div #elementoA, #div #elementoB').plugin()

Answer 1

It seems that there is no more way.

To documentation even gives an example where a plugin that needs to know the selector should receive it repeated as a function parameter.

Statement example:

$.fn.foo = function( selector, options ) { /* código */ }; 

Call example:

$( "div.bar" ).foo( "div.bar", {dog: "bark"} );

Not a satisfactory answer, but the official answer.

I believe that it would be best to reformulate your code to not depend on the selector, if possible, otherwise it would be possible to create an alternative more beautiful than repetition. A very simple and unsophisticated example would be:

function applyPlugin(selector, options) {
    $(selector).plugin(selector, options);
}

If possible, edit the question explaining exactly what you failed to do with the each.

Anyway, it is the model of the use of each:

$.fn.myNewPlugin = function() {
    return this.each(function() {
        // ação em cada elemento aqui
    });
};