2
Whoa, somebody knows why when I do this:
json_encode(array("0" => 0));
Return that: [0]
Instead: {"0":0}
2
Whoa, somebody knows why when I do this:
json_encode(array("0" => 0));
Return that: [0]
Instead: {"0":0}
6
PHP automatically detects whether you are using numeric keys and converts to an array.
If you really want an object you can use JSON_FORCE_OBJECT
in the second argument (PHP 5.3+), optional json_encode
. (example: https://ideone.com/kFftSu)
Note that if you add another element to that array, without numeric key, the json_encode
already reads as object.
Example (https://ideone.com/yyrya4):
echo json_encode(array("0" => 0, "foo" => "bar"));
// dá:
{"0":0,"foo":"bar"}
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