How do I make a char vector recognize a line break?

Question

The code is like this

#include <iostream>
#include <fstream>
using namespace std;

int main(){

    char frase[30];
    
    char j;
    
    int i=0;
    do{
        cin>>j;
        if(j!=' '){
            frase[i]=j;
            i++;
        }
    }while (j!=' ');
    
    
    
    return 0;
}   

Answer 1

The line break is a character of "escape", are characters of type "ENTER" or "TAB". In the case of line break is the " n", and can be compared like this == "\n", but some characters are not possible because it does not have "escape" characters, such as the case of a "DEL" for example, so one way to cover all characters is to convert the one char for int that will return the code ASCII, which will be 10 and compare, so:

int ascii;
....
ascii = (int)frase[i];

if (ascii == 10) // é uma quebra de linha

You can test with this little program:

#include <stdio.h>

int main() {

     int ascii, i;
     char texto[] = "Bom dia\nGood Moring\nBonjour";
     
     printf("%s\n------------\n", texto);
     
     for(i=0; texto[i]; i++) {
        ascii = (int)texto[i];

        if (ascii == 10) {
            printf("Quebra de linha\n");
        } else {
            printf("%c = %d\n",texto[i],ascii);
        }
    }
}

Or see online working here: https://www.mycompiler.io/view/0utzo5p

And you can see the table with the other codes ASCII here: https://sites.google.com/a/aebenfica.org/apontamentos-tic/tic/ascii

OBS: I edited the question based on the comments to better reflect the comparison