Collect name of file used

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I’m concluding a code that uses a lot of function copy of shutil. As I will distribute the file in executable format later and probably at some point will change its name, I want to know if there is a way to collect the name of the file where the script is being run. Something like:

nome = os.getbasename()
print(nome)
-globancy.exe
python-3.x

2 answers

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You actually have several options. Of these I present to you three:

import os    
print(os.path.basename(__file__))


import sys
print (sys.argv[0])]


print (__file__)

There is a discussion interesting in the OS regarding the pros and cons of the use of each one. Worth consulting.

Where:

__file__ is the name of the file path from which the module was loaded, if it was loaded from a file. The __file__attribute can be missing for certain types of modules such as C modules that are statically linked to the interpreter; for extension modules dynamically loaded from a shared library, is the path name of shared library file.

  • sys.argv[0](requires import sys) is the name of the script that was called from the command line and can be an absolute path as per detailed in official documentation:

argv[0] is the name of the script (depends on the operating system if this is a path name or not). If the command was executed using the option -c command line for the interpreter, argv[0] will be set to the string '-c'. If no script name has been passed to the python interpreter, argv[0] is the empty string.

The information that made up this reply was removed from here. I thank the user Yoel.

0

Interpreting your question as "Discovering the name of the current Python script".

Thus, some solutions follow according to issue in English:

The attribute __file__ in any file will give you the way to this one. So if you want to skip the rest of the way, use os.path.basename(__file__).2 3

In the meantime, you can still import __main__ and use the same attribute __file__.4

Or else sys.argv[0], but remember to use equally os.path.basename if you only want the file name.5

and sys are modules and should be imported to be used.

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